#EANF#

#EANF#

struct integer
{
int len;
char* str;
int* arr;
}int1, int2;
int main(void) {
printf("Please enter 1st number\n");
int1.str= str_input();
int1.len=chars_read-1;
int1.arr= func2(int1.len, int1.str);
printf(("\%c\n"), *int1.str);
printf("Please enter 2nd number\n");
int2.str = str_input();
int2.len=chars_read-1;
printf(("\n %c\n"), *int1.str );
int2.arr= func2(int2.len, int2.str);
if the input is 4363 and 78596 , the output is 4 and 7 respectively. The
output is not 4 and 4. Given that both are different objects, shouldn't
both have different memory allocation? Please note: this is NOT a
typographical error. I have used the same *int1.str both times. the
problem is that although I have made no changes in it, its value is
changing. How? I do not think that str_input() can make a difference.
char* str_input(void) {
char cur_char;
char* input_ptr = (char*)malloc(LINE_LEN * sizeof(char));
char input_string[LINE_LEN];
//while ((cur_char = getchar()) != '\n' && cur_char<='9' && cur_char>='0'
&& chars_read < 10000)
for(chars_read=1; chars_read<10000; chars_read++)
{
scanf("%c", &cur_char);
if(cur_char!='\n' && cur_char<='9' && cur_char>='0')
{
input_string[chars_read-1]= cur_char;
printf("%c\n", input_string[chars_read-1]);
}
else{
break;
}
}
input_string[chars_read] = '\n';
input_ptr = &input_string[0]; /* sets pointer to address of 0th index */
return input_ptr;
}
//chars_read is a global variable.